Base | Representation |
---|---|
bin | 10101010100011000… |
… | …01101101111111001 |
3 | 1002112122021121201201 |
4 | 22222030031233321 |
5 | 141414441411403 |
6 | 5131411414201 |
7 | 553424063506 |
oct | 125214155771 |
9 | 32478247651 |
10 | 11445263353 |
11 | 4943609837 |
12 | 2274bb4361 |
13 | 11052563a4 |
14 | 7a80984ad |
15 | 46ebe421d |
hex | 2aa30dbf9 |
11445263353 has 4 divisors (see below), whose sum is σ = 11466187600. Its totient is φ = 11424339108.
The previous prime is 11445263351. The next prime is 11445263359. The reversal of 11445263353 is 35336254411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11445263353 - 21 = 11445263351 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11445263351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10461303 + ... + 10462396.
It is an arithmetic number, because the mean of its divisors is an integer number (2866546900).
Almost surely, 211445263353 is an apocalyptic number.
It is an amenable number.
11445263353 is a deficient number, since it is larger than the sum of its proper divisors (20924247).
11445263353 is an equidigital number, since it uses as much as digits as its factorization.
11445263353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20924246.
The product of its digits is 129600, while the sum is 37.
The spelling of 11445263353 in words is "eleven billion, four hundred forty-five million, two hundred sixty-three thousand, three hundred fifty-three".
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