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11451136140322 = 25725568070161
BaseRepresentation
bin1010011010100010110011…
…1001101110010000100010
31111112201101100220010110021
42212220230321232100202
53000103411322442242
640204325044424054
72261213554124464
oct246505471562042
944481340803407
1011451136140322
1137154439033aa
12134b3823a802a
13650ab6cc7898
142b8348cd4134
1514cd0c56bb67
hexa6a2ce6e422

11451136140322 has 4 divisors (see below), whose sum is σ = 17176704210486. Its totient is φ = 5725568070160.

The previous prime is 11451136140313. The next prime is 11451136140407. The reversal of 11451136140322 is 22304163115411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9926526108321 + 1524610032001 = 3150639^2 + 1234751^2 .

It is a super-2 number, since 2×114511361403222 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2862784035079 + ... + 2862784035082.

Almost surely, 211451136140322 is an apocalyptic number.

11451136140322 is a deficient number, since it is larger than the sum of its proper divisors (5725568070164).

11451136140322 is an equidigital number, since it uses as much as digits as its factorization.

11451136140322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5725568070163.

The product of its (nonzero) digits is 17280, while the sum is 34.

Adding to 11451136140322 its reverse (22304163115411), we get a palindrome (33755299255733).

The spelling of 11451136140322 in words is "eleven trillion, four hundred fifty-one billion, one hundred thirty-six million, one hundred forty thousand, three hundred twenty-two".

Divisors: 1 2 5725568070161 11451136140322