11451500342041 has 4 divisors (see below), whose sum is σ = 11580168885300. Its totient is φ = 11322831798784.

The previous prime is 11451500342039. The next prime is 11451500342057. The reversal of 11451500342041 is 14024300515411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1224776036416 + 10226724305625 = 1106696^2 + 3197925^2 .

It is a cyclic number.

It is not a de Polignac number, because 11451500342041 - 2¹ = 11451500342039 is a prime.

It is a super-2 number, since 2×11451500342041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11451500341994 and 11451500342012.

It is not an unprimeable number, because it can be changed into a prime (11451500342141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64334271496 + ... + 64334271673.

It is an arithmetic number, because the mean of its divisors is an integer number (2895042221325).

Almost surely, 2^{11451500342041} is an apocalyptic number.

It is an amenable number.

11451500342041 is a deficient number, since it is larger than the sum of its proper divisors (128668543259).

11451500342041 is an equidigital number, since it uses as much as digits as its factorization.

11451500342041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128668543258.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 11451500342041 its reverse (14024300515411), we get a palindrome (25475800857452).

The spelling of 11451500342041 in words is "eleven trillion, four hundred fifty-one billion, five hundred million, three hundred forty-two thousand, forty-one".