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114535350549913 is a prime number
BaseRepresentation
bin11010000010101101010110…
…111000100011110110011001
3120000112110202111202012022011
4122002231112320203312121
5110003021344220044123
61043332451430025521
733060622521233146
oct3202552670436631
9500473674665264
10114535350549913
1133549195500667
1210a198751a82a1
134bba838c57bc7
14203d77d3813cd
15d394d9a27e0d
hex682b56e23d99

114535350549913 has 2 divisors, whose sum is σ = 114535350549914. Its totient is φ = 114535350549912.

The previous prime is 114535350549901. The next prime is 114535350550007. The reversal of 114535350549913 is 319945053535411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110472880529664 + 4062470020249 = 10510608^2 + 2015557^2 .

It is a cyclic number.

It is not a de Polignac number, because 114535350549913 - 29 = 114535350549401 is a prime.

It is not a weakly prime, because it can be changed into another prime (114535350549313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57267675274956 + 57267675274957.

It is an arithmetic number, because the mean of its divisors is an integer number (57267675274957).

Almost surely, 2114535350549913 is an apocalyptic number.

It is an amenable number.

114535350549913 is a deficient number, since it is larger than the sum of its proper divisors (1).

114535350549913 is an equidigital number, since it uses as much as digits as its factorization.

114535350549913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21870000, while the sum is 58.

The spelling of 114535350549913 in words is "one hundred fourteen trillion, five hundred thirty-five billion, three hundred fifty million, five hundred forty-nine thousand, nine hundred thirteen".