Base | Representation |
---|---|
bin | 110101010101100100… |
… | …1110010100101011011 |
3 | 101221122112101101012202 |
4 | 1222223021302211123 |
5 | 3334034344320443 |
6 | 124341431000415 |
7 | 11163265130666 |
oct | 1525311624533 |
9 | 357575341182 |
10 | 114540620123 |
11 | 44638215226 |
12 | 1a24750910b |
13 | aa55126587 |
14 | 57882646dd |
15 | 2ea5a5b7b8 |
hex | 1aab27295b |
114540620123 has 2 divisors, whose sum is σ = 114540620124. Its totient is φ = 114540620122.
The previous prime is 114540620119. The next prime is 114540620147. The reversal of 114540620123 is 321026045411.
It is a weak prime.
It is an emirp because it is prime and its reverse (321026045411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114540620123 - 22 = 114540620119 is a prime.
It is a super-2 number, since 2×1145406201232 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (114540620023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57270310061 + 57270310062.
It is an arithmetic number, because the mean of its divisors is an integer number (57270310062).
Almost surely, 2114540620123 is an apocalyptic number.
114540620123 is a deficient number, since it is larger than the sum of its proper divisors (1).
114540620123 is an equidigital number, since it uses as much as digits as its factorization.
114540620123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 114540620123 its reverse (321026045411), we get a palindrome (435566665534).
The spelling of 114540620123 in words is "one hundred fourteen billion, five hundred forty million, six hundred twenty thousand, one hundred twenty-three".
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