Base | Representation |
---|---|
bin | 11010000010110011101001… |
… | …110110100110011010011011 |
3 | 120000120010012200012120001011 |
4 | 122002303221312212122123 |
5 | 110003124220440113141 |
6 | 1043335530335234351 |
7 | 33061252203252166 |
oct | 3202635166463233 |
9 | 500503180176034 |
10 | 114542111254171 |
11 | 33551044772857 |
12 | 10a1b0413789b7 |
13 | 4bbb3757c8723 |
14 | 203dc2120aadd |
15 | d39783324881 |
hex | 682ce9da669b |
114542111254171 has 2 divisors, whose sum is σ = 114542111254172. Its totient is φ = 114542111254170.
The previous prime is 114542111254117. The next prime is 114542111254189. The reversal of 114542111254171 is 171452111245411.
Together with previous prime (114542111254117) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114542111254171 - 211 = 114542111252123 is a prime.
It is not a weakly prime, because it can be changed into another prime (114542111254271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57271055627085 + 57271055627086.
It is an arithmetic number, because the mean of its divisors is an integer number (57271055627086).
Almost surely, 2114542111254171 is an apocalyptic number.
114542111254171 is a deficient number, since it is larger than the sum of its proper divisors (1).
114542111254171 is an equidigital number, since it uses as much as digits as its factorization.
114542111254171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 44800, while the sum is 40.
Adding to 114542111254171 its reverse (171452111245411), we get a palindrome (285994222499582).
The spelling of 114542111254171 in words is "one hundred fourteen trillion, five hundred forty-two billion, one hundred eleven million, two hundred fifty-four thousand, one hundred seventy-one".
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