Base | Representation |
---|---|
bin | 11010000010110100101011… |
… | …111101000001101101111011 |
3 | 120000120020001221221121221001 |
4 | 122002310223331001231323 |
5 | 110003134003340011011 |
6 | 1043340232352425431 |
7 | 33061321530401632 |
oct | 3202645375015573 |
9 | 500506057847831 |
10 | 114543220235131 |
11 | 33551563761646 |
12 | 10a1b2b0848277 |
13 | 4bbb4c14a218c |
14 | 203dcc8606519 |
15 | d397ea8817c1 |
hex | 682d2bf41b7b |
114543220235131 has 2 divisors, whose sum is σ = 114543220235132. Its totient is φ = 114543220235130.
The previous prime is 114543220235113. The next prime is 114543220235237. The reversal of 114543220235131 is 131532022345411.
Together with previous prime (114543220235113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114543220235131 - 221 = 114543218137979 is a prime.
It is a super-2 number, since 2×1145432202351312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114543220935131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57271610117565 + 57271610117566.
It is an arithmetic number, because the mean of its divisors is an integer number (57271610117566).
Almost surely, 2114543220235131 is an apocalyptic number.
114543220235131 is a deficient number, since it is larger than the sum of its proper divisors (1).
114543220235131 is an equidigital number, since it uses as much as digits as its factorization.
114543220235131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 114543220235131 in words is "one hundred fourteen trillion, five hundred forty-three billion, two hundred twenty million, two hundred thirty-five thousand, one hundred thirty-one".
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