Base | Representation |
---|---|
bin | 110101010101110111… |
… | …0000100101010000011 |
3 | 101221200012021121010201 |
4 | 1222223232010222003 |
5 | 3334044313200311 |
6 | 124342410510031 |
7 | 11163442023316 |
oct | 1525356045203 |
9 | 357605247121 |
10 | 114550131331 |
11 | 44642621129 |
12 | 1a24a735317 |
13 | aa570a67cc |
14 | 578961c97d |
15 | 2ea67d99c1 |
hex | 1aabb84a83 |
114550131331 has 2 divisors, whose sum is σ = 114550131332. Its totient is φ = 114550131330.
The previous prime is 114550131317. The next prime is 114550131361. The reversal of 114550131331 is 133131055411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114550131331 - 25 = 114550131299 is a prime.
It is a super-3 number, since 3×1145501313313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 114550131331.
It is not a weakly prime, because it can be changed into another prime (114550131361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57275065665 + 57275065666.
It is an arithmetic number, because the mean of its divisors is an integer number (57275065666).
Almost surely, 2114550131331 is an apocalyptic number.
114550131331 is a deficient number, since it is larger than the sum of its proper divisors (1).
114550131331 is an equidigital number, since it uses as much as digits as its factorization.
114550131331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 28.
Adding to 114550131331 its reverse (133131055411), we get a palindrome (247681186742).
The spelling of 114550131331 in words is "one hundred fourteen billion, five hundred fifty million, one hundred thirty-one thousand, three hundred thirty-one".
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