Base | Representation |
---|---|
bin | 10101010101100100… |
… | …10010100001110001 |
3 | 1002120100001201011011 |
4 | 22222302102201301 |
5 | 141430020310101 |
6 | 5132405350521 |
7 | 553604653666 |
oct | 125262224161 |
9 | 32510051134 |
10 | 11455244401 |
11 | 4949206737 |
12 | 2278408441 |
13 | 110733c433 |
14 | 7a9535a6d |
15 | 470a16751 |
hex | 2aac92871 |
11455244401 has 4 divisors (see below), whose sum is σ = 11463206400. Its totient is φ = 11447282404.
The previous prime is 11455244393. The next prime is 11455244443. The reversal of 11455244401 is 10444255411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10444255411 = 10333 ⋅1010767.
It is a cyclic number.
It is not a de Polignac number, because 11455244401 - 23 = 11455244393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11455244501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3978841 + ... + 3981718.
It is an arithmetic number, because the mean of its divisors is an integer number (2865801600).
Almost surely, 211455244401 is an apocalyptic number.
It is an amenable number.
11455244401 is a deficient number, since it is larger than the sum of its proper divisors (7961999).
11455244401 is an equidigital number, since it uses as much as digits as its factorization.
11455244401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7961998.
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 11455244401 its reverse (10444255411), we get a palindrome (21899499812).
The spelling of 11455244401 in words is "eleven billion, four hundred fifty-five million, two hundred forty-four thousand, four hundred one".
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