Base | Representation |
---|---|
bin | 110101010111011111… |
… | …1111010110001011001 |
3 | 101221211000210101022212 |
4 | 1222232333322301121 |
5 | 3334202404003311 |
6 | 124352053524505 |
7 | 11165010424514 |
oct | 1525677726131 |
9 | 357730711285 |
10 | 114605141081 |
11 | 44670683832 |
12 | 1a265043735 |
13 | aa655c7262 |
14 | 5792a5bd7b |
15 | 2eab553c8b |
hex | 1aaeffac59 |
114605141081 has 2 divisors, whose sum is σ = 114605141082. Its totient is φ = 114605141080.
The previous prime is 114605141071. The next prime is 114605141087. The reversal of 114605141081 is 180141506411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71962891081 + 42642250000 = 268259^2 + 206500^2 .
It is a cyclic number.
It is not a de Polignac number, because 114605141081 - 26 = 114605141017 is a prime.
It is a super-2 number, since 2×1146051410812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114605141087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57302570540 + 57302570541.
It is an arithmetic number, because the mean of its divisors is an integer number (57302570541).
Almost surely, 2114605141081 is an apocalyptic number.
It is an amenable number.
114605141081 is a deficient number, since it is larger than the sum of its proper divisors (1).
114605141081 is an equidigital number, since it uses as much as digits as its factorization.
114605141081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 32.
Adding to 114605141081 its reverse (180141506411), we get a palindrome (294746647492).
The spelling of 114605141081 in words is "one hundred fourteen billion, six hundred five million, one hundred forty-one thousand, eighty-one".
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