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114833928793 is a prime number
BaseRepresentation
bin110101011110010100…
…0101011001001011001
3101222101222022000001211
41222330220223021121
53340134441210133
6124430505343121
711203456201213
oct1527450531131
9358358260054
10114833928793
1144778839391
121a309797aa1
13aaa0b207bc
1457b51b55b3
152ec1697bcd
hex1abca2b259

114833928793 has 2 divisors, whose sum is σ = 114833928794. Its totient is φ = 114833928792.

The previous prime is 114833928739. The next prime is 114833928817. The reversal of 114833928793 is 397829338411.

Together with previous prime (114833928739) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100277988889 + 14555939904 = 316667^2 + 120648^2 .

It is a cyclic number.

It is not a de Polignac number, because 114833928793 - 213 = 114833920601 is a prime.

It is not a weakly prime, because it can be changed into another prime (114833922793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57416964396 + 57416964397.

It is an arithmetic number, because the mean of its divisors is an integer number (57416964397).

Almost surely, 2114833928793 is an apocalyptic number.

It is an amenable number.

114833928793 is a deficient number, since it is larger than the sum of its proper divisors (1).

114833928793 is an equidigital number, since it uses as much as digits as its factorization.

114833928793 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7838208, while the sum is 58.

The spelling of 114833928793 in words is "one hundred fourteen billion, eight hundred thirty-three million, nine hundred twenty-eight thousand, seven hundred ninety-three".