Base | Representation |
---|---|
bin | 1010011100110100110111… |
… | …1100010110101000111011 |
3 | 1111200110120220121220120212 |
4 | 2213031031330112220323 |
5 | 3001224211331340203 |
6 | 40234331450341335 |
7 | 2264102315365553 |
oct | 247151574265073 |
9 | 44613526556525 |
10 | 11490345183803 |
11 | 3730034338072 |
12 | 1356aa542a84b |
13 | 6546c5242625 |
14 | 2ba1c840c163 |
15 | 14dd548b61d8 |
hex | a734df16a3b |
11490345183803 has 2 divisors, whose sum is σ = 11490345183804. Its totient is φ = 11490345183802.
The previous prime is 11490345183797. The next prime is 11490345183839. The reversal of 11490345183803 is 30838154309411.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11490345183803 is a prime.
It is a super-3 number, since 3×114903451838033 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11490345183853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5745172591901 + 5745172591902.
It is an arithmetic number, because the mean of its divisors is an integer number (5745172591902).
Almost surely, 211490345183803 is an apocalyptic number.
11490345183803 is a deficient number, since it is larger than the sum of its proper divisors (1).
11490345183803 is an equidigital number, since it uses as much as digits as its factorization.
11490345183803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1244160, while the sum is 50.
The spelling of 11490345183803 in words is "eleven trillion, four hundred ninety billion, three hundred forty-five million, one hundred eighty-three thousand, eight hundred three".
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