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114919982993 is a prime number
BaseRepresentation
bin110101100000111000…
…0111100011110010001
3101222121222020000020102
41223001300330132101
53340324003423433
6124443222022145
711205552511124
oct1530160743621
9358558200212
10114919982993
1144812375162
121a332577955
13aab58c074a
1457c27b63bb
152ec8ee54e8
hex1ac1c3c791

114919982993 has 2 divisors, whose sum is σ = 114919982994. Its totient is φ = 114919982992.

The previous prime is 114919982951. The next prime is 114919983029. The reversal of 114919982993 is 399289919411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80899287184 + 34020695809 = 284428^2 + 184447^2 .

It is a cyclic number.

It is not a de Polignac number, because 114919982993 - 218 = 114919720849 is a prime.

It is a super-2 number, since 2×1149199829932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114919982923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57459991496 + 57459991497.

It is an arithmetic number, because the mean of its divisors is an integer number (57459991497).

Almost surely, 2114919982993 is an apocalyptic number.

It is an amenable number.

114919982993 is a deficient number, since it is larger than the sum of its proper divisors (1).

114919982993 is an equidigital number, since it uses as much as digits as its factorization.

114919982993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11337408, while the sum is 65.

The spelling of 114919982993 in words is "one hundred fourteen billion, nine hundred nineteen million, nine hundred eighty-two thousand, nine hundred ninety-three".