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1149240121 = 1151998471
BaseRepresentation
bin100010010000000…
…0000001100111001
32222002111110001221
41010200000030321
54323201140441
6310012112041
740323244201
oct10440001471
92862443057
101149240121
1153a797127
12280a65621
13154131253
14ac8b9401
156ad608d1
hex44800339

1149240121 has 4 divisors (see below), whose sum is σ = 1150239744. Its totient is φ = 1148240500.

The previous prime is 1149240119. The next prime is 1149240163. The reversal of 1149240121 is 1210429411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1149240121 - 21 = 1149240119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1149040121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 498085 + ... + 500386.

It is an arithmetic number, because the mean of its divisors is an integer number (287559936).

Almost surely, 21149240121 is an apocalyptic number.

It is an amenable number.

1149240121 is a deficient number, since it is larger than the sum of its proper divisors (999623).

1149240121 is an equidigital number, since it uses as much as digits as its factorization.

1149240121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 999622.

The product of its (nonzero) digits is 576, while the sum is 25.

The square root of 1149240121 is about 33900.4442596259. Note that the first 3 decimals coincide. The cubic root of 1149240121 is about 1047.4587436925.

Adding to 1149240121 its reverse (1210429411), we get a palindrome (2359669532).

The spelling of 1149240121 in words is "one billion, one hundred forty-nine million, two hundred forty thousand, one hundred twenty-one".

Divisors: 1 1151 998471 1149240121