Base | Representation |
---|---|
bin | 10000101110011011100… |
… | …001101011001011010011 |
3 | 11001212201021002020221020 |
4 | 100232123201223023103 |
5 | 122312400041022430 |
6 | 2240002232530523 |
7 | 146016231045666 |
oct | 20563341531323 |
9 | 4055637066836 |
10 | 1149365564115 |
11 | 403496995a6a |
12 | 166908250a43 |
13 | 84500283342 |
14 | 3d8b58496dd |
15 | 1ed6e7c4b10 |
hex | 10b9b86b2d3 |
1149365564115 has 32 divisors (see below), whose sum is σ = 1864328862720. Its totient is φ = 604548354816.
The previous prime is 1149365564111. The next prime is 1149365564117. The reversal of 1149365564115 is 5114655639411.
It is not a de Polignac number, because 1149365564115 - 22 = 1149365564111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1149365564111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16147494 + ... + 16218516.
It is an arithmetic number, because the mean of its divisors is an integer number (58260276960).
Almost surely, 21149365564115 is an apocalyptic number.
1149365564115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1149365564115 is a deficient number, since it is larger than the sum of its proper divisors (714963298605).
1149365564115 is a wasteful number, since it uses less digits than its factorization.
1149365564115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85883.
The product of its digits is 1944000, while the sum is 51.
The spelling of 1149365564115 in words is "one trillion, one hundred forty-nine billion, three hundred sixty-five million, five hundred sixty-four thousand, one hundred fifteen".
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