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11497179378313 is a prime number
BaseRepresentation
bin1010011101001110010101…
…0010101111001010001001
31111201010020012100222000001
42213103211102233022021
53001332210410101223
640241421543043001
72264433552156106
oct247234522571211
944633205328001
1011497179378313
113732a21034602
121358292140461
136552440a44c5
142ba675d27aad
1514e10487c9ad
hexa74e54af289

11497179378313 has 2 divisors, whose sum is σ = 11497179378314. Its totient is φ = 11497179378312.

The previous prime is 11497179378283. The next prime is 11497179378331. The reversal of 11497179378313 is 31387397179411.

11497179378313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (11497179378331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10810075985424 + 687103392889 = 3287868^2 + 828917^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11497179378313 is a prime.

It is not a weakly prime, because it can be changed into another prime (11497179378353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5748589689156 + 5748589689157.

It is an arithmetic number, because the mean of its divisors is an integer number (5748589689157).

Almost surely, 211497179378313 is an apocalyptic number.

It is an amenable number.

11497179378313 is a deficient number, since it is larger than the sum of its proper divisors (1).

11497179378313 is an equidigital number, since it uses as much as digits as its factorization.

11497179378313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24004512, while the sum is 64.

The spelling of 11497179378313 in words is "eleven trillion, four hundred ninety-seven billion, one hundred seventy-nine million, three hundred seventy-eight thousand, three hundred thirteen".