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115010443129 is a prime number
BaseRepresentation
bin110101100011100101…
…0000001011101111001
3101222212021102212012211
41223013022001131321
53341020133140004
6124500212535121
711211031431241
oct1530712013571
9358767385184
10115010443129
11448594401aa
121a3589214a1
13aacb573c5a
1457d0802b21
152ed1e13504
hex1ac7281779

115010443129 has 2 divisors, whose sum is σ = 115010443130. Its totient is φ = 115010443128.

The previous prime is 115010443019. The next prime is 115010443151. The reversal of 115010443129 is 921344010511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98440317504 + 16570125625 = 313752^2 + 128725^2 .

It is a cyclic number.

It is not a de Polignac number, because 115010443129 - 219 = 115009918841 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115010443129.

It is not a weakly prime, because it can be changed into another prime (115010443829) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57505221564 + 57505221565.

It is an arithmetic number, because the mean of its divisors is an integer number (57505221565).

Almost surely, 2115010443129 is an apocalyptic number.

It is an amenable number.

115010443129 is a deficient number, since it is larger than the sum of its proper divisors (1).

115010443129 is an equidigital number, since it uses as much as digits as its factorization.

115010443129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 31.

The spelling of 115010443129 in words is "one hundred fifteen billion, ten million, four hundred forty-three thousand, one hundred twenty-nine".