1150274131 has 2 divisors, whose sum is σ = 1150274132. Its totient is φ = 1150274130.

The previous prime is 1150274119. The next prime is 1150274197. The reversal of 1150274131 is 1314720511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1150274131 - 2¹³ = 1150265939 is a prime.

It is a super-2 number, since 2×1150274131² = 2646261152895610322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1150274096 and 1150274105.

It is not a weakly prime, because it can be changed into another prime (1150274101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575137065 + 575137066.

It is an arithmetic number, because the mean of its divisors is an integer number (575137066).

Almost surely, 2^1150274131 is an apocalyptic number.

1150274131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150274131 is an equidigital number, since it uses as much as digits as its factorization.

1150274131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 25.

The square root of 1150274131 is about 33915.6915158751. The cubic root of 1150274131 is about 1047.7727941476.

Adding to 1150274131 its reverse (1314720511), we get a palindrome (2464994642).

The spelling of 1150274131 in words is "one billion, one hundred fifty million, two hundred seventy-four thousand, one hundred thirty-one".