Base | Representation |
---|---|
bin | 10101011011010001… |
… | …01011000100011001 |
3 | 1002200200000202010212 |
4 | 22231220223010121 |
5 | 142024240231004 |
6 | 5141234220505 |
7 | 555025232606 |
oct | 125550530431 |
9 | 32620022125 |
10 | 11503055129 |
11 | 49731a1635 |
12 | 2290424735 |
13 | 111420c1c7 |
14 | 7b1a1d6ad |
15 | 474d0c96e |
hex | 2ada2b119 |
11503055129 has 2 divisors, whose sum is σ = 11503055130. Its totient is φ = 11503055128.
The previous prime is 11503055093. The next prime is 11503055149. The reversal of 11503055129 is 92155030511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8901545104 + 2601510025 = 94348^2 + 51005^2 .
It is a cyclic number.
It is not a de Polignac number, because 11503055129 - 28 = 11503054873 is a prime.
It is a super-3 number, since 3×115030551293 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11503055095 and 11503055104.
It is not a weakly prime, because it can be changed into another prime (11503055149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5751527564 + 5751527565.
It is an arithmetic number, because the mean of its divisors is an integer number (5751527565).
Almost surely, 211503055129 is an apocalyptic number.
It is an amenable number.
11503055129 is a deficient number, since it is larger than the sum of its proper divisors (1).
11503055129 is an equidigital number, since it uses as much as digits as its factorization.
11503055129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6750, while the sum is 32.
The spelling of 11503055129 in words is "eleven billion, five hundred three million, fifty-five thousand, one hundred twenty-nine".
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