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115032224130001 is a prime number
BaseRepresentation
bin11010001001111100000110…
…110110110110001111010001
3120002021222021111001022200121
4122021330012312312033101
5110034141443334130001
61044353024011150241
733141542515046623
oct3211740666661721
9502258244038617
10115032224130001
113371a98a701552
1210a9a023145381
134c2565245a369
142059837290c13
15d473bae446a1
hex689f06db63d1

115032224130001 has 2 divisors, whose sum is σ = 115032224130002. Its totient is φ = 115032224130000.

The previous prime is 115032224129981. The next prime is 115032224130041. The reversal of 115032224130001 is 100031422230511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 62768795000976 + 52263429129025 = 7922676^2 + 7229345^2 .

It is a cyclic number.

It is not a de Polignac number, because 115032224130001 - 223 = 115032215741393 is a prime.

It is not a weakly prime, because it can be changed into another prime (115032224130041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57516112065000 + 57516112065001.

It is an arithmetic number, because the mean of its divisors is an integer number (57516112065001).

Almost surely, 2115032224130001 is an apocalyptic number.

It is an amenable number.

115032224130001 is a deficient number, since it is larger than the sum of its proper divisors (1).

115032224130001 is an equidigital number, since it uses as much as digits as its factorization.

115032224130001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 115032224130001 its reverse (100031422230511), we get a palindrome (215063646360512).

The spelling of 115032224130001 in words is "one hundred fifteen trillion, thirty-two billion, two hundred twenty-four million, one hundred thirty thousand, one".