Base | Representation |
---|---|
bin | 11010001001111100000110… |
… | …110111001110001000101011 |
3 | 120002021222021111020021221212 |
4 | 122021330012313032020223 |
5 | 110034141443400243013 |
6 | 1044353024013223335 |
7 | 33141542515635164 |
oct | 3211740667161053 |
9 | 502258244207855 |
10 | 115032224227883 |
11 | 3371a98a769046 |
12 | 10a9a023191b4b |
13 | 4c25652492a91 |
14 | 20598372b876b |
15 | d473bae636a8 |
hex | 689f06dce22b |
115032224227883 has 2 divisors, whose sum is σ = 115032224227884. Its totient is φ = 115032224227882.
The previous prime is 115032224227867. The next prime is 115032224227903. The reversal of 115032224227883 is 388722422230511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115032224227883 - 24 = 115032224227867 is a prime.
It is a super-2 number, since 2×1150322242278832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115032224227853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57516112113941 + 57516112113942.
It is an arithmetic number, because the mean of its divisors is an integer number (57516112113942).
Almost surely, 2115032224227883 is an apocalyptic number.
115032224227883 is a deficient number, since it is larger than the sum of its proper divisors (1).
115032224227883 is an equidigital number, since it uses as much as digits as its factorization.
115032224227883 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2580480, while the sum is 50.
The spelling of 115032224227883 in words is "one hundred fifteen trillion, thirty-two billion, two hundred twenty-four million, two hundred twenty-seven thousand, eight hundred eighty-three".
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