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11503253323 is a prime number
BaseRepresentation
bin10101011011010010…
…11011011101001011
31002200200101211000101
422231221123131023
5142024313101243
65141242350231
7555030016462
oct125551333513
932620354011
1011503253323
114973317531
1222904bb377
13111427b493
147b1a719d9
15474d4b54d
hex2ada5b74b

11503253323 has 2 divisors, whose sum is σ = 11503253324. Its totient is φ = 11503253322.

The previous prime is 11503253299. The next prime is 11503253329. The reversal of 11503253323 is 32335230511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11503253323 - 25 = 11503253291 is a prime.

It is a super-2 number, since 2×115032533232 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11503253291 and 11503253300.

It is not a weakly prime, because it can be changed into another prime (11503253329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5751626661 + 5751626662.

It is an arithmetic number, because the mean of its divisors is an integer number (5751626662).

Almost surely, 211503253323 is an apocalyptic number.

11503253323 is a deficient number, since it is larger than the sum of its proper divisors (1).

11503253323 is an equidigital number, since it uses as much as digits as its factorization.

11503253323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 28.

Adding to 11503253323 its reverse (32335230511), we get a palindrome (43838483834).

The spelling of 11503253323 in words is "eleven billion, five hundred three million, two hundred fifty-three thousand, three hundred twenty-three".