Base | Representation |
---|---|
bin | 110101100100011101… |
… | …1010001110101000001 |
3 | 101222221100022020021002 |
4 | 1223020323101311001 |
5 | 3341100233214132 |
6 | 124503153141345 |
7 | 11211541664030 |
oct | 1531073216501 |
9 | 358840266232 |
10 | 115040132417 |
11 | 44874179201 |
12 | 1a36685a855 |
13 | ab0476a692 |
14 | 57d4730717 |
15 | 2ed482a262 |
hex | 1ac8ed1d41 |
115040132417 has 4 divisors (see below), whose sum is σ = 131474437056. Its totient is φ = 98605827780.
The previous prime is 115040132357. The next prime is 115040132419. The reversal of 115040132417 is 714231040511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115040132417 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 115040132417.
It is not an unprimeable number, because it can be changed into a prime (115040132419) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8217152309 + ... + 8217152322.
It is an arithmetic number, because the mean of its divisors is an integer number (32868609264).
Almost surely, 2115040132417 is an apocalyptic number.
It is an amenable number.
115040132417 is a deficient number, since it is larger than the sum of its proper divisors (16434304639).
115040132417 is an equidigital number, since it uses as much as digits as its factorization.
115040132417 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16434304638.
The product of its (nonzero) digits is 3360, while the sum is 29.
Adding to 115040132417 its reverse (714231040511), we get a palindrome (829271172928).
The spelling of 115040132417 in words is "one hundred fifteen billion, forty million, one hundred thirty-two thousand, four hundred seventeen".
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