Base | Representation |
---|---|
bin | 110101100100011110… |
… | …0000110111111011011 |
3 | 101222221100201021222001 |
4 | 1223020330012333123 |
5 | 3341100312201141 |
6 | 124503201541431 |
7 | 11211543561625 |
oct | 1531074067733 |
9 | 358840637861 |
10 | 115040350171 |
11 | 4487430786a |
12 | 1a366944877 |
13 | ab04815826 |
14 | 57d4789c15 |
15 | 2ed486ea31 |
hex | 1ac8f06fdb |
115040350171 has 2 divisors, whose sum is σ = 115040350172. Its totient is φ = 115040350170.
The previous prime is 115040350151. The next prime is 115040350181. The reversal of 115040350171 is 171053040511.
It is a strong prime.
It is an emirp because it is prime and its reverse (171053040511) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115040350171 is a prime.
It is not a weakly prime, because it can be changed into another prime (115040350151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57520175085 + 57520175086.
It is an arithmetic number, because the mean of its divisors is an integer number (57520175086).
Almost surely, 2115040350171 is an apocalyptic number.
115040350171 is a deficient number, since it is larger than the sum of its proper divisors (1).
115040350171 is an equidigital number, since it uses as much as digits as its factorization.
115040350171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2100, while the sum is 28.
Adding to 115040350171 its reverse (171053040511), we get a palindrome (286093390682).
The spelling of 115040350171 in words is "one hundred fifteen billion, forty million, three hundred fifty thousand, one hundred seventy-one".
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