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115041102550211 is a prime number
BaseRepresentation
bin11010001010000100011000…
…000011010101010011000011
3120002022211012020100210120202
4122022010120003111103003
5110034313134223101321
61044401053010355415
733142305523266635
oct3212043003252303
9502284166323522
10115041102550211
1133723726302012
1210a9b8a058bb6b
134c2643897c646
14205a03a498a55
15d4773a60770b
hex68a1180d54c3

115041102550211 has 2 divisors, whose sum is σ = 115041102550212. Its totient is φ = 115041102550210.

The previous prime is 115041102550169. The next prime is 115041102550333. The reversal of 115041102550211 is 112055201140511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115041102550211 - 210 = 115041102549187 is a prime.

It is a super-2 number, since 2×1150411025502112 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115041102550111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57520551275105 + 57520551275106.

It is an arithmetic number, because the mean of its divisors is an integer number (57520551275106).

Almost surely, 2115041102550211 is an apocalyptic number.

115041102550211 is a deficient number, since it is larger than the sum of its proper divisors (1).

115041102550211 is an equidigital number, since it uses as much as digits as its factorization.

115041102550211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2000, while the sum is 29.

Adding to 115041102550211 its reverse (112055201140511), we get a palindrome (227096303690722).

The spelling of 115041102550211 in words is "one hundred fifteen trillion, forty-one billion, one hundred two million, five hundred fifty thousand, two hundred eleven".