Base | Representation |
---|---|
bin | 11010001010000100011000… |
… | …000011010101010011000011 |
3 | 120002022211012020100210120202 |
4 | 122022010120003111103003 |
5 | 110034313134223101321 |
6 | 1044401053010355415 |
7 | 33142305523266635 |
oct | 3212043003252303 |
9 | 502284166323522 |
10 | 115041102550211 |
11 | 33723726302012 |
12 | 10a9b8a058bb6b |
13 | 4c2643897c646 |
14 | 205a03a498a55 |
15 | d4773a60770b |
hex | 68a1180d54c3 |
115041102550211 has 2 divisors, whose sum is σ = 115041102550212. Its totient is φ = 115041102550210.
The previous prime is 115041102550169. The next prime is 115041102550333. The reversal of 115041102550211 is 112055201140511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115041102550211 - 210 = 115041102549187 is a prime.
It is a super-2 number, since 2×1150411025502112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115041102550111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57520551275105 + 57520551275106.
It is an arithmetic number, because the mean of its divisors is an integer number (57520551275106).
Almost surely, 2115041102550211 is an apocalyptic number.
115041102550211 is a deficient number, since it is larger than the sum of its proper divisors (1).
115041102550211 is an equidigital number, since it uses as much as digits as its factorization.
115041102550211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2000, while the sum is 29.
Adding to 115041102550211 its reverse (112055201140511), we get a palindrome (227096303690722).
The spelling of 115041102550211 in words is "one hundred fifteen trillion, forty-one billion, one hundred two million, five hundred fifty thousand, two hundred eleven".
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