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115048441 is a prime number
BaseRepresentation
bin1101101101101…
…11111111111001
322000111001210101
412312313333321
5213423022231
615225515401
72564616124
oct666677771
9260431711
10115048441
1159a3a662
1232642b61
131aab2201
14113cb3bb
15a178661
hex6db7ff9

115048441 has 2 divisors, whose sum is σ = 115048442. Its totient is φ = 115048440.

The previous prime is 115048397. The next prime is 115048457. The reversal of 115048441 is 144840511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70492816 + 44555625 = 8396^2 + 6675^2 .

It is a cyclic number.

It is not a de Polignac number, because 115048441 - 29 = 115047929 is a prime.

It is a super-2 number, since 2×1150484412 = 26472287553060962, which contains 22 as substring.

It is equal to p6575302 and since 115048441 and 6575302 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (115048841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57524220 + 57524221.

It is an arithmetic number, because the mean of its divisors is an integer number (57524221).

Almost surely, 2115048441 is an apocalyptic number.

It is an amenable number.

115048441 is a deficient number, since it is larger than the sum of its proper divisors (1).

115048441 is an equidigital number, since it uses as much as digits as its factorization.

115048441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2560, while the sum is 28.

The square root of 115048441 is about 10726.0636302420. The cubic root of 115048441 is about 486.3626834888.

Adding to 115048441 its reverse (144840511), we get a palindrome (259888952).

The spelling of 115048441 in words is "one hundred fifteen million, forty-eight thousand, four hundred forty-one".