Base | Representation |
---|---|
bin | 10101011011110000… |
… | …00000110010010001 |
3 | 1002200221121001001221 |
4 | 22231320000302101 |
5 | 142031302414431 |
6 | 5141500325041 |
7 | 555104351143 |
oct | 125570006221 |
9 | 32627531057 |
10 | 11507076241 |
11 | 4975498771 |
12 | 2291843781 |
13 | 1114cb956b |
14 | 7b2388c93 |
15 | 475354111 |
hex | 2ade00c91 |
11507076241 has 4 divisors (see below), whose sum is σ = 11540238192. Its totient is φ = 11473914292.
The previous prime is 11507076233. The next prime is 11507076281. The reversal of 11507076241 is 14267070511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11507076241 - 23 = 11507076233 is a prime.
It is a super-3 number, since 3×115070762413 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11507076197 and 11507076206.
It is not an unprimeable number, because it can be changed into a prime (11507076221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16580455 + ... + 16581148.
It is an arithmetic number, because the mean of its divisors is an integer number (2885059548).
Almost surely, 211507076241 is an apocalyptic number.
It is an amenable number.
11507076241 is a deficient number, since it is larger than the sum of its proper divisors (33161951).
11507076241 is an equidigital number, since it uses as much as digits as its factorization.
11507076241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33161950.
The product of its (nonzero) digits is 11760, while the sum is 34.
The spelling of 11507076241 in words is "eleven billion, five hundred seven million, seventy-six thousand, two hundred forty-one".
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