Base | Representation |
---|---|
bin | 10000101111110010000… |
… | …100000011101101100011 |
3 | 11002000110110000002011102 |
4 | 100233302010003231203 |
5 | 122323333224334313 |
6 | 2240402255105015 |
7 | 146100220440254 |
oct | 20576204035543 |
9 | 4060413002142 |
10 | 1150817418083 |
11 | 404071481383 |
12 | 16705251216b |
13 | 846a1cb9028 |
14 | 3d9b25b8b2b |
15 | 1ee06eada58 |
hex | 10bf2103b63 |
1150817418083 has 2 divisors, whose sum is σ = 1150817418084. Its totient is φ = 1150817418082.
The previous prime is 1150817418061. The next prime is 1150817418103. The reversal of 1150817418083 is 3808147180511.
It is a strong prime.
It is an emirp because it is prime and its reverse (3808147180511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1150817418083 - 216 = 1150817352547 is a prime.
It is a super-3 number, since 3×11508174180833 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1150817412083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575408709041 + 575408709042.
It is an arithmetic number, because the mean of its divisors is an integer number (575408709042).
Almost surely, 21150817418083 is an apocalyptic number.
1150817418083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1150817418083 is an equidigital number, since it uses as much as digits as its factorization.
1150817418083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 215040, while the sum is 47.
The spelling of 1150817418083 in words is "one trillion, one hundred fifty billion, eight hundred seventeen million, four hundred eighteen thousand, eighty-three".
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