Base | Representation |
---|---|
bin | 11010001010111011010001… |
… | …101100010100101100011011 |
3 | 120002112110100111111121201211 |
4 | 122022323101230110230123 |
5 | 110041244401210433301 |
6 | 1044444122254323551 |
7 | 33146463402361342 |
oct | 3212732154245433 |
9 | 502473314447654 |
10 | 115100051655451 |
11 | 33746726564305 |
12 | 10aab1b24b95b7 |
13 | 4c2bb7178cbc5 |
14 | 205cc2d552b59 |
15 | d4903a974051 |
hex | 68aed1b14b1b |
115100051655451 has 2 divisors, whose sum is σ = 115100051655452. Its totient is φ = 115100051655450.
The previous prime is 115100051655401. The next prime is 115100051655473. The reversal of 115100051655451 is 154556150001511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115100051655451 - 239 = 114550295841563 is a prime.
It is not a weakly prime, because it can be changed into another prime (115100051655401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57550025827725 + 57550025827726.
It is an arithmetic number, because the mean of its divisors is an integer number (57550025827726).
Almost surely, 2115100051655451 is an apocalyptic number.
115100051655451 is a deficient number, since it is larger than the sum of its proper divisors (1).
115100051655451 is an equidigital number, since it uses as much as digits as its factorization.
115100051655451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75000, while the sum is 40.
The spelling of 115100051655451 in words is "one hundred fifteen trillion, one hundred billion, fifty-one million, six hundred fifty-five thousand, four hundred fifty-one".
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