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11510020121 = 31137009711
BaseRepresentation
bin10101011100000110…
…01111100000011001
31002201011010121022112
422232003033200121
5142033031120441
65142043402105
7555141361655
oct125603174031
932634117275
1011510020121
114977119526
122292823335
1311157aa4c2
147b2913a65
154757364eb
hex2ae0cf819

11510020121 has 4 divisors (see below), whose sum is σ = 11547030144. Its totient is φ = 11473010100.

The previous prime is 11510020117. The next prime is 11510020147. The reversal of 11510020121 is 12102001511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11510020121 - 22 = 11510020117 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11510020096 and 11510020105.

It is not an unprimeable number, because it can be changed into a prime (11510020321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18504545 + ... + 18505166.

It is an arithmetic number, because the mean of its divisors is an integer number (2886757536).

Almost surely, 211510020121 is an apocalyptic number.

It is an amenable number.

11510020121 is a deficient number, since it is larger than the sum of its proper divisors (37010023).

11510020121 is an equidigital number, since it uses as much as digits as its factorization.

11510020121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37010022.

The product of its (nonzero) digits is 20, while the sum is 14.

Adding to 11510020121 its reverse (12102001511), we get a palindrome (23612021632).

The spelling of 11510020121 in words is "eleven billion, five hundred ten million, twenty thousand, one hundred twenty-one".

Divisors: 1 311 37009711 11510020121