Base | Representation |
---|---|
bin | 1010011101111110101001… |
… | …1001110110001010111011 |
3 | 1111202100201010221100011101 |
4 | 2213133222121312022323 |
5 | 3002040241401430021 |
6 | 40251405005112231 |
7 | 2265403150661143 |
oct | 247375231661273 |
9 | 44670633840141 |
10 | 11510150030011 |
11 | 3738477694166 |
12 | 135a8b1b58677 |
13 | 65653036ba39 |
14 | 2bb146813923 |
15 | 14e613433a91 |
hex | a77ea6762bb |
11510150030011 has 2 divisors, whose sum is σ = 11510150030012. Its totient is φ = 11510150030010.
The previous prime is 11510150029993. The next prime is 11510150030023. The reversal of 11510150030011 is 11003005101511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11510150030011 - 25 = 11510150029979 is a prime.
It is not a weakly prime, because it can be changed into another prime (11510150090011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5755075015005 + 5755075015006.
It is an arithmetic number, because the mean of its divisors is an integer number (5755075015006).
Almost surely, 211510150030011 is an apocalyptic number.
11510150030011 is a deficient number, since it is larger than the sum of its proper divisors (1).
11510150030011 is an equidigital number, since it uses as much as digits as its factorization.
11510150030011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 75, while the sum is 19.
Adding to 11510150030011 its reverse (11003005101511), we get a palindrome (22513155131522).
It can be divided in two parts, 115101500 and 30011, that added together give a palindrome (115131511).
The spelling of 11510150030011 in words is "eleven trillion, five hundred ten billion, one hundred fifty million, thirty thousand, eleven".
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