Search a number
-
+
11510323050001 is a prime number
BaseRepresentation
bin1010011101111111010010…
…1101110111011000010001
31111202101011012111122222011
42213133310231313120101
53002041120200100001
640251434105342521
72265410351425456
oct247376455673021
944671135448864
1011510323050001
113738556319696
12135a93ba97a41
1365655a16a829
142bb1617b182d
1514e62370dd51
hexa77f4b77611

11510323050001 has 2 divisors, whose sum is σ = 11510323050002. Its totient is φ = 11510323050000.

The previous prime is 11510323049989. The next prime is 11510323050059. The reversal of 11510323050001 is 10005032301511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11443498214976 + 66824835025 = 3382824^2 + 258505^2 .

It is a cyclic number.

It is not a de Polignac number, because 11510323050001 - 217 = 11510322918929 is a prime.

It is a super-2 number, since 2×115103230500012 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11510323050091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5755161525000 + 5755161525001.

It is an arithmetic number, because the mean of its divisors is an integer number (5755161525001).

Almost surely, 211510323050001 is an apocalyptic number.

It is an amenable number.

11510323050001 is a deficient number, since it is larger than the sum of its proper divisors (1).

11510323050001 is an equidigital number, since it uses as much as digits as its factorization.

11510323050001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450, while the sum is 22.

Adding to 11510323050001 its reverse (10005032301511), we get a palindrome (21515355351512).

The spelling of 11510323050001 in words is "eleven trillion, five hundred ten billion, three hundred twenty-three million, fifty thousand, one".