Base | Representation |
---|---|
bin | 11010001010111111000111… |
… | …001111001100001001111011 |
3 | 120002112211222121011211220110 |
4 | 122022333013033030021323 |
5 | 110041331320312312220 |
6 | 1044450043134555403 |
7 | 33150000444135435 |
oct | 3212770717141173 |
9 | 502484877154813 |
10 | 115104171213435 |
11 | 3374844a988188 |
12 | 10aabb62068b63 |
13 | 4c2c37a0b2291 |
14 | 205d100709655 |
15 | d491cc463be0 |
hex | 68afc73cc27b |
115104171213435 has 16 divisors (see below), whose sum is σ = 184429393892640. Its totient is φ = 61301317996800.
The previous prime is 115104171213431. The next prime is 115104171213443. The reversal of 115104171213435 is 534312171401511.
It is not a de Polignac number, because 115104171213435 - 22 = 115104171213431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115104171213393 and 115104171213402.
It is not an unprimeable number, because it can be changed into a prime (115104171213431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5473321450 + ... + 5473342479.
It is an arithmetic number, because the mean of its divisors is an integer number (11526837118290).
Almost surely, 2115104171213435 is an apocalyptic number.
115104171213435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
115104171213435 is a deficient number, since it is larger than the sum of its proper divisors (69325222679205).
115104171213435 is a wasteful number, since it uses less digits than its factorization.
115104171213435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10946664638.
The product of its (nonzero) digits is 50400, while the sum is 39.
The spelling of 115104171213435 in words is "one hundred fifteen trillion, one hundred four billion, one hundred seventy-one million, two hundred thirteen thousand, four hundred thirty-five".
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