11510521442131 has 4 divisors (see below), whose sum is σ = 11510559759664. Its totient is φ = 11510483124600.

The previous prime is 11510521442129. The next prime is 11510521442197. The reversal of 11510521442131 is 13124412501511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11510521442131 - 2¹ = 11510521442129 is a prime.

It is a super-2 number, since 2×11510521442131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11510521442093 and 11510521442102.

It is not an unprimeable number, because it can be changed into a prime (11510521442111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18704580 + ... + 19310161.

It is an arithmetic number, because the mean of its divisors is an integer number (2877639939916).

Almost surely, 2^{11510521442131} is an apocalyptic number.

11510521442131 is a deficient number, since it is larger than the sum of its proper divisors (38317533).

11510521442131 is an equidigital number, since it uses as much as digits as its factorization.

11510521442131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38317532.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 11510521442131 its reverse (13124412501511), we get a palindrome (24634933943642).

The spelling of 11510521442131 in words is "eleven trillion, five hundred ten billion, five hundred twenty-one million, four hundred forty-two thousand, one hundred thirty-one".