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115114411481 is a prime number
BaseRepresentation
bin110101100110101011…
…0101000010111011001
3102000010112001222222112
41223031112220113121
53341223242131411
6124514405202105
711213433232046
oct1531526502731
9360115058875
10115114411481
11449020a2163
121a387700335
13ab16c76aa4
1458005481cd
152edb0edb8b
hex1acd5a85d9

115114411481 has 2 divisors, whose sum is σ = 115114411482. Its totient is φ = 115114411480.

The previous prime is 115114411463. The next prime is 115114411487. The reversal of 115114411481 is 184114411511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69951786256 + 45162625225 = 264484^2 + 212515^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115114411481 is a prime.

It is a super-2 number, since 2×1151144114812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115114411487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57557205740 + 57557205741.

It is an arithmetic number, because the mean of its divisors is an integer number (57557205741).

Almost surely, 2115114411481 is an apocalyptic number.

It is an amenable number.

115114411481 is a deficient number, since it is larger than the sum of its proper divisors (1).

115114411481 is an equidigital number, since it uses as much as digits as its factorization.

115114411481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2560, while the sum is 32.

Adding to 115114411481 its reverse (184114411511), we get a palindrome (299228822992).

The spelling of 115114411481 in words is "one hundred fifteen billion, one hundred fourteen million, four hundred eleven thousand, four hundred eighty-one".