Base | Representation |
---|---|
bin | 10000110000001001101… |
… | …101011001100011001010 |
3 | 11002001111002111012112022 |
4 | 100300021231121203022 |
5 | 122330141304201102 |
6 | 2240505510044442 |
7 | 146113105442666 |
oct | 20601155314312 |
9 | 4061432435468 |
10 | 1151214131402 |
11 | 404255401a25 |
12 | 167143349722 |
13 | 8473624963a |
14 | 3da0d1658a6 |
15 | 1ee2bc235a2 |
hex | 10c09b598ca |
1151214131402 has 16 divisors (see below), whose sum is σ = 1738898830152. Its totient is φ = 571594721280.
The previous prime is 1151214131401. The next prime is 1151214131407. The reversal of 1151214131402 is 2041314121511.
It can be written as a sum of positive squares in 4 ways, for example, as 1148967466201 + 2246665201 = 1071899^2 + 47399^2 .
It is a super-2 number, since 2×11512141314022 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1151214131401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3212873 + ... + 3553164.
Almost surely, 21151214131402 is an apocalyptic number.
1151214131402 is a deficient number, since it is larger than the sum of its proper divisors (587684698750).
1151214131402 is a wasteful number, since it uses less digits than its factorization.
1151214131402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6766633.
The product of its (nonzero) digits is 960, while the sum is 26.
Adding to 1151214131402 its reverse (2041314121511), we get a palindrome (3192528252913).
The spelling of 1151214131402 in words is "one trillion, one hundred fifty-one billion, two hundred fourteen million, one hundred thirty-one thousand, four hundred two".
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