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11513041244403 = 317474803104399
BaseRepresentation
bin1010011110001001011010…
…1110111101000011110011
31111202122011122021020200220
42213202112232331003303
53002112202024310103
640253003525544123
72265534615620466
oct247422656750363
944678148236626
1011513041244403
113739720702346
12135b37a275043
136568a135489a
142bb33c7bd2dd
1514e732189c53
hexa7896bbd0f3

11513041244403 has 16 divisors (see below), whose sum is σ = 16599528806400. Its totient is φ = 7070169673856.

The previous prime is 11513041244399. The next prime is 11513041244413. The reversal of 11513041244403 is 30444214031511.

It is a cyclic number.

It is not a de Polignac number, because 11513041244403 - 22 = 11513041244399 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11513041244413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2401549803 + ... + 2401554596.

It is an arithmetic number, because the mean of its divisors is an integer number (1037470550400).

Almost surely, 211513041244403 is an apocalyptic number.

11513041244403 is a deficient number, since it is larger than the sum of its proper divisors (5086487561997).

11513041244403 is a wasteful number, since it uses less digits than its factorization.

11513041244403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4803104466.

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 11513041244403 its reverse (30444214031511), we get a palindrome (41957255275914).

The spelling of 11513041244403 in words is "eleven trillion, five hundred thirteen billion, forty-one million, two hundred forty-four thousand, four hundred three".

Divisors: 1 3 17 47 51 141 799 2397 4803104399 14409313197 81652774783 225745906753 244958324349 677237720259 3837680414801 11513041244403