1151314033 has 4 divisors (see below), whose sum is σ = 1151928640. Its totient is φ = 1150699428.

The previous prime is 1151314027. The next prime is 1151314037. The reversal of 1151314033 is 3304131511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3304131511 = 59 ⋅56002229.

It is a cyclic number.

It is not a de Polignac number, because 1151314033 - 2⁹ = 1151313521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1151313995 and 1151314013.

It is not an unprimeable number, because it can be changed into a prime (1151314037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 304485 + ... + 308242.

It is an arithmetic number, because the mean of its divisors is an integer number (287982160).

Almost surely, 2^1151314033 is an apocalyptic number.

It is an amenable number.

1151314033 is a deficient number, since it is larger than the sum of its proper divisors (614607).

1151314033 is an equidigital number, since it uses as much as digits as its factorization.

1151314033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 614606.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 1151314033 is about 33931.0187439163. The cubic root of 1151314033 is about 1048.0884443668.

Adding to 1151314033 its reverse (3304131511), we get a palindrome (4455445544).

The spelling of 1151314033 in words is "one billion, one hundred fifty-one million, three hundred fourteen thousand, thirty-three".