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11513161044453 = 329977135450547
BaseRepresentation
bin1010011110001001110111…
…0111111101000111100101
31111202122110222200201110210
42213202131313331013211
53002112423211410303
640253023445410033
72265540602116665
oct247423567750745
944678428621423
1011513161044453
113739782297952
12135b3b2409919
136568c010b7a3
142bb3506861a5
1514e73c951203
hexa789ddfd1e5

11513161044453 has 16 divisors (see below), whose sum is σ = 15896476313280. Its totient is φ = 7403185042176.

The previous prime is 11513161044431. The next prime is 11513161044461. The reversal of 11513161044453 is 35444016131511.

It is not a de Polignac number, because 11513161044453 - 213 = 11513161036261 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11513161040453) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 67640275 + ... + 67810272.

It is an arithmetic number, because the mean of its divisors is an integer number (993529769580).

Almost surely, 211513161044453 is an apocalyptic number.

It is an amenable number.

11513161044453 is a deficient number, since it is larger than the sum of its proper divisors (4383315268827).

11513161044453 is a wasteful number, since it uses less digits than its factorization.

11513161044453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135451556.

The product of its (nonzero) digits is 86400, while the sum is 39.

Adding to 11513161044453 its reverse (35444016131511), we get a palindrome (46957177175964).

The spelling of 11513161044453 in words is "eleven trillion, five hundred thirteen billion, one hundred sixty-one million, forty-four thousand, four hundred fifty-three".

Divisors: 1 3 29 87 977 2931 28333 84999 135450547 406351641 3928065863 11784197589 132335184419 397005553257 3837720348151 11513161044453