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115133015554114 = 257566507777057
BaseRepresentation
bin11010001011011001111110…
…011111100111100001000010
3120002122121102210220011201111
4122023121332133213201002
5110042314403440212424
61044511213245153534
733152041312033225
oct3213317637474102
9502577383804644
10115133015554114
1133759701850268
1210ab5671b5b8aa
134c31cc5c0939c
1420606794875bc
15d49d198b0194
hex68b67e7e7842

115133015554114 has 4 divisors (see below), whose sum is σ = 172699523331174. Its totient is φ = 57566507777056.

The previous prime is 115133015554031. The next prime is 115133015554157. The reversal of 115133015554114 is 411455510331511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 75955844020225 + 39177171533889 = 8715265^2 + 6259167^2 .

It is a super-2 number, since 2×1151330155541142 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28783253888527 + ... + 28783253888530.

Almost surely, 2115133015554114 is an apocalyptic number.

115133015554114 is a deficient number, since it is larger than the sum of its proper divisors (57566507777060).

115133015554114 is an equidigital number, since it uses as much as digits as its factorization.

115133015554114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57566507777059.

The product of its (nonzero) digits is 90000, while the sum is 40.

Adding to 115133015554114 its reverse (411455510331511), we get a palindrome (526588525885625).

The spelling of 115133015554114 in words is "one hundred fifteen trillion, one hundred thirty-three billion, fifteen million, five hundred fifty-four thousand, one hundred fourteen".

Divisors: 1 2 57566507777057 115133015554114