Base | Representation |
---|---|
bin | 11010001011011001111110… |
… | …011111100111100001000010 |
3 | 120002122121102210220011201111 |
4 | 122023121332133213201002 |
5 | 110042314403440212424 |
6 | 1044511213245153534 |
7 | 33152041312033225 |
oct | 3213317637474102 |
9 | 502577383804644 |
10 | 115133015554114 |
11 | 33759701850268 |
12 | 10ab5671b5b8aa |
13 | 4c31cc5c0939c |
14 | 20606794875bc |
15 | d49d198b0194 |
hex | 68b67e7e7842 |
115133015554114 has 4 divisors (see below), whose sum is σ = 172699523331174. Its totient is φ = 57566507777056.
The previous prime is 115133015554031. The next prime is 115133015554157. The reversal of 115133015554114 is 411455510331511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 75955844020225 + 39177171533889 = 8715265^2 + 6259167^2 .
It is a super-2 number, since 2×1151330155541142 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28783253888527 + ... + 28783253888530.
Almost surely, 2115133015554114 is an apocalyptic number.
115133015554114 is a deficient number, since it is larger than the sum of its proper divisors (57566507777060).
115133015554114 is an equidigital number, since it uses as much as digits as its factorization.
115133015554114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57566507777059.
The product of its (nonzero) digits is 90000, while the sum is 40.
Adding to 115133015554114 its reverse (411455510331511), we get a palindrome (526588525885625).
The spelling of 115133015554114 in words is "one hundred fifteen trillion, one hundred thirty-three billion, fifteen million, five hundred fifty-four thousand, one hundred fourteen".
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