Base | Representation |
---|---|
bin | 11010001011011010001111… |
… | …100101010010111000010011 |
3 | 120002122122011210101002120101 |
4 | 122023122033211102320103 |
5 | 110042321000334130443 |
6 | 1044511301530153231 |
7 | 33152051362663225 |
oct | 3213321745227023 |
9 | 502578153332511 |
10 | 115133302255123 |
11 | 33759839670a49 |
12 | 10ab5731b82817 |
13 | 4c3204042bb59 |
14 | 20606a5598415 |
15 | d49d34b4384d |
hex | 68b68f952e13 |
115133302255123 has 2 divisors, whose sum is σ = 115133302255124. Its totient is φ = 115133302255122.
The previous prime is 115133302254979. The next prime is 115133302255141. The reversal of 115133302255123 is 321552203331511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115133302255123 - 29 = 115133302254611 is a prime.
It is not a weakly prime, because it can be changed into another prime (115133302255523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57566651127561 + 57566651127562.
It is an arithmetic number, because the mean of its divisors is an integer number (57566651127562).
Almost surely, 2115133302255123 is an apocalyptic number.
115133302255123 is a deficient number, since it is larger than the sum of its proper divisors (1).
115133302255123 is an equidigital number, since it uses as much as digits as its factorization.
115133302255123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 37.
Adding to 115133302255123 its reverse (321552203331511), we get a palindrome (436685505586634).
The spelling of 115133302255123 in words is "one hundred fifteen trillion, one hundred thirty-three billion, three hundred two million, two hundred fifty-five thousand, one hundred twenty-three".
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