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11513560120537 is a prime number
BaseRepresentation
bin1010011110001011010110…
…1010010011110011011001
31111202200111210121212221111
42213202311222103303121
53002114232342324122
640253131223140321
72265553516163056
oct247426552236331
944680453555844
1011513560120537
1137399675916a2
12135b4a3ba46a1
136569549b8697
142bb38b68a02d
1514e7629d0d77
hexa78b5a93cd9

11513560120537 has 2 divisors, whose sum is σ = 11513560120538. Its totient is φ = 11513560120536.

The previous prime is 11513560120463. The next prime is 11513560120541. The reversal of 11513560120537 is 73502106531511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5783755643136 + 5729804477401 = 2404944^2 + 2393701^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11513560120537 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11513560120537.

It is not a weakly prime, because it can be changed into another prime (11513560120637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756780060268 + 5756780060269.

It is an arithmetic number, because the mean of its divisors is an integer number (5756780060269).

Almost surely, 211513560120537 is an apocalyptic number.

It is an amenable number.

11513560120537 is a deficient number, since it is larger than the sum of its proper divisors (1).

11513560120537 is an equidigital number, since it uses as much as digits as its factorization.

11513560120537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 94500, while the sum is 40.

The spelling of 11513560120537 in words is "eleven trillion, five hundred thirteen billion, five hundred sixty million, one hundred twenty thousand, five hundred thirty-seven".