1151400433 has 2 divisors, whose sum is σ = 1151400434. Its totient is φ = 1151400432.

The previous prime is 1151400413. The next prime is 1151400449. The reversal of 1151400433 is 3340041511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1072759009 + 78641424 = 32753^2 + 8868^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1151400433 is a prime.

It is a super-2 number, since 2×1151400433² = 2651445914225174978, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1151400403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575700216 + 575700217.

It is an arithmetic number, because the mean of its divisors is an integer number (575700217).

Almost surely, 2^1151400433 is an apocalyptic number.

It is an amenable number.

1151400433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151400433 is an equidigital number, since it uses as much as digits as its factorization.

1151400433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 1151400433 is about 33932.2918913533. The cubic root of 1151400433 is about 1048.1146615337.

Adding to 1151400433 its reverse (3340041511), we get a palindrome (4491441944).

The spelling of 1151400433 in words is "one billion, one hundred fifty-one million, four hundred thousand, four hundred thirty-three".