Base | Representation |
---|---|
bin | 1010011110001111000000… |
… | …1000001100111010011001 |
3 | 1111202210001011101111211202 |
4 | 2213203300020030322121 |
5 | 3002123240001111121 |
6 | 40253412423403545 |
7 | 2265620026624343 |
oct | 247436010147231 |
9 | 44683034344752 |
10 | 11514541035161 |
11 | 373a32025a33a |
12 | 135b7185b35b5 |
13 | 656a7cca2838 |
14 | 2bb441a6a293 |
15 | 14e7bdb9240b |
hex | a78f020ce99 |
11514541035161 has 8 divisors (see below), whose sum is σ = 11553642644544. Its totient is φ = 11475449783280.
The previous prime is 11514541035119. The next prime is 11514541035167. The reversal of 11514541035161 is 16153014541511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11514541035161 - 218 = 11514540773017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11514541035167) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 358925 + ... + 4812266.
It is an arithmetic number, because the mean of its divisors is an integer number (1444205330568).
Almost surely, 211514541035161 is an apocalyptic number.
It is an amenable number.
11514541035161 is a deficient number, since it is larger than the sum of its proper divisors (39101609383).
11514541035161 is an equidigital number, since it uses as much as digits as its factorization.
11514541035161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5178751.
The product of its (nonzero) digits is 36000, while the sum is 38.
Adding to 11514541035161 its reverse (16153014541511), we get a palindrome (27667555576672).
The spelling of 11514541035161 in words is "eleven trillion, five hundred fourteen billion, five hundred forty-one million, thirty-five thousand, one hundred sixty-one".
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