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11514770505473 = 14424779826759
BaseRepresentation
bin1010011110001111110111…
…0011100011111100000001
31111202210122011011210221012
42213203331303203330001
53002124222222133343
640253451302010305
72265625514243114
oct247437563437401
944683564153835
1011514770505473
11373a428840824
12135b781416995
13656ab86a79a1
142bb46432057b
1514e7d3dbd718
hexa78fdce3f01

11514770505473 has 4 divisors (see below), whose sum is σ = 11514850476480. Its totient is φ = 11514690534468.

The previous prime is 11514770505389. The next prime is 11514770505479. The reversal of 11514770505473 is 37450507741511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11514770505473 - 218 = 11514770243329 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11514770505479) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39769133 + ... + 40057626.

It is an arithmetic number, because the mean of its divisors is an integer number (2878712619120).

Almost surely, 211514770505473 is an apocalyptic number.

It is an amenable number.

11514770505473 is a deficient number, since it is larger than the sum of its proper divisors (79971007).

11514770505473 is an equidigital number, since it uses as much as digits as its factorization.

11514770505473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79971006.

The product of its (nonzero) digits is 2058000, while the sum is 50.

The spelling of 11514770505473 in words is "eleven trillion, five hundred fourteen billion, seven hundred seventy million, five hundred five thousand, four hundred seventy-three".

Divisors: 1 144247 79826759 11514770505473