Base | Representation |
---|---|
bin | 1010011110010000110000… |
… | …1011000100110001110001 |
3 | 1111202211020221202011022011 |
4 | 2213210030023010301301 |
5 | 3002130220424102241 |
6 | 40253531232242521 |
7 | 2265634502136556 |
oct | 247441413046161 |
9 | 44684227664264 |
10 | 11515011550321 |
11 | 373a541908344 |
12 | 135b82a0a0441 |
13 | 656b26603286 |
14 | 2bb488348a2d |
15 | 14e7ea134281 |
hex | a790c2c4c71 |
11515011550321 has 4 divisors (see below), whose sum is σ = 11515087747072. Its totient is φ = 11514935353572.
The previous prime is 11515011550307. The next prime is 11515011550363. The reversal of 11515011550321 is 12305511051511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11515011550321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11515011550121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37871241 + ... + 38174086.
It is an arithmetic number, because the mean of its divisors is an integer number (2878771936768).
Almost surely, 211515011550321 is an apocalyptic number.
It is an amenable number.
11515011550321 is a deficient number, since it is larger than the sum of its proper divisors (76196751).
11515011550321 is an equidigital number, since it uses as much as digits as its factorization.
11515011550321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76196750.
The product of its (nonzero) digits is 3750, while the sum is 31.
The spelling of 11515011550321 in words is "eleven trillion, five hundred fifteen billion, eleven million, five hundred fifty thousand, three hundred twenty-one".
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