Base | Representation |
---|---|
bin | 1010011110010001111100… |
… | …1110111000100101001011 |
3 | 1111202212002020102221102001 |
4 | 2213210133032320211023 |
5 | 3002131344304103133 |
6 | 40254023054051431 |
7 | 2265645434121262 |
oct | 247443716704513 |
9 | 44685066387361 |
10 | 11515331316043 |
11 | 373a696362035 |
12 | 135b8b91a9b77 |
13 | 656b77931969 |
14 | 2bb4b89c55d9 |
15 | 14e81824987d |
hex | a791f3b894b |
11515331316043 has 2 divisors, whose sum is σ = 11515331316044. Its totient is φ = 11515331316042.
The previous prime is 11515331316031. The next prime is 11515331316091. The reversal of 11515331316043 is 34061313351511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11515331316043 - 233 = 11506741381451 is a prime.
It is a super-2 number, since 2×115153313160432 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11515331315993 and 11515331316011.
It is not a weakly prime, because it can be changed into another prime (11515331316743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5757665658021 + 5757665658022.
It is an arithmetic number, because the mean of its divisors is an integer number (5757665658022).
Almost surely, 211515331316043 is an apocalyptic number.
11515331316043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11515331316043 is an equidigital number, since it uses as much as digits as its factorization.
11515331316043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 37.
Adding to 11515331316043 its reverse (34061313351511), we get a palindrome (45576644667554).
The spelling of 11515331316043 in words is "eleven trillion, five hundred fifteen billion, three hundred thirty-one million, three hundred sixteen thousand, forty-three".
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