Base | Representation |
---|---|
bin | 11010001011101110110100… |
… | …101101101101011000101001 |
3 | 120002201202012211021121022102 |
4 | 122023232310231231120221 |
5 | 110043201224403214223 |
6 | 1044525354354503145 |
7 | 33153463110116603 |
oct | 3213566455553051 |
9 | 502652184247272 |
10 | 115155400054313 |
11 | 33768149265603 |
12 | 10ab9a7a594ab5 |
13 | 4c34152603988 |
14 | 20617a0316173 |
15 | d4a6c9b3e928 |
hex | 68bbb4b6d629 |
115155400054313 has 2 divisors, whose sum is σ = 115155400054314. Its totient is φ = 115155400054312.
The previous prime is 115155400054307. The next prime is 115155400054337. The reversal of 115155400054313 is 313450004551511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109587461370409 + 5567938683904 = 10468403^2 + 2359648^2 .
It is a cyclic number.
It is not a de Polignac number, because 115155400054313 - 24 = 115155400054297 is a prime.
It is not a weakly prime, because it can be changed into another prime (115155400054213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57577700027156 + 57577700027157.
It is an arithmetic number, because the mean of its divisors is an integer number (57577700027157).
Almost surely, 2115155400054313 is an apocalyptic number.
It is an amenable number.
115155400054313 is a deficient number, since it is larger than the sum of its proper divisors (1).
115155400054313 is an equidigital number, since it uses as much as digits as its factorization.
115155400054313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90000, while the sum is 38.
The spelling of 115155400054313 in words is "one hundred fifteen trillion, one hundred fifty-five billion, four hundred million, fifty-four thousand, three hundred thirteen".
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