Base | Representation |
---|---|
bin | 110101101000001100… |
… | …1001101111100101001 |
3 | 102000021002001120101001 |
4 | 1223100121031330221 |
5 | 3341324321440403 |
6 | 124523430355001 |
7 | 11214622633633 |
oct | 1532031157451 |
9 | 360232046331 |
10 | 115165421353 |
11 | 44928972684 |
12 | 1a3a07bba61 |
13 | ab246c6a48 |
14 | 5807225a53 |
15 | 2ee0827c1d |
hex | 1ad064df29 |
115165421353 has 2 divisors, whose sum is σ = 115165421354. Its totient is φ = 115165421352.
The previous prime is 115165421339. The next prime is 115165421377. The reversal of 115165421353 is 353124561511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 65824572969 + 49340848384 = 256563^2 + 222128^2 .
It is an emirp because it is prime and its reverse (353124561511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115165421353 - 213 = 115165413161 is a prime.
It is not a weakly prime, because it can be changed into another prime (115165421323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57582710676 + 57582710677.
It is an arithmetic number, because the mean of its divisors is an integer number (57582710677).
Almost surely, 2115165421353 is an apocalyptic number.
It is an amenable number.
115165421353 is a deficient number, since it is larger than the sum of its proper divisors (1).
115165421353 is an equidigital number, since it uses as much as digits as its factorization.
115165421353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54000, while the sum is 37.
Adding to 115165421353 its reverse (353124561511), we get a palindrome (468289982864).
The spelling of 115165421353 in words is "one hundred fifteen billion, one hundred sixty-five million, four hundred twenty-one thousand, three hundred fifty-three".
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