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115165421353 is a prime number
BaseRepresentation
bin110101101000001100…
…1001101111100101001
3102000021002001120101001
41223100121031330221
53341324321440403
6124523430355001
711214622633633
oct1532031157451
9360232046331
10115165421353
1144928972684
121a3a07bba61
13ab246c6a48
145807225a53
152ee0827c1d
hex1ad064df29

115165421353 has 2 divisors, whose sum is σ = 115165421354. Its totient is φ = 115165421352.

The previous prime is 115165421339. The next prime is 115165421377. The reversal of 115165421353 is 353124561511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65824572969 + 49340848384 = 256563^2 + 222128^2 .

It is an emirp because it is prime and its reverse (353124561511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115165421353 - 213 = 115165413161 is a prime.

It is not a weakly prime, because it can be changed into another prime (115165421323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57582710676 + 57582710677.

It is an arithmetic number, because the mean of its divisors is an integer number (57582710677).

Almost surely, 2115165421353 is an apocalyptic number.

It is an amenable number.

115165421353 is a deficient number, since it is larger than the sum of its proper divisors (1).

115165421353 is an equidigital number, since it uses as much as digits as its factorization.

115165421353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54000, while the sum is 37.

Adding to 115165421353 its reverse (353124561511), we get a palindrome (468289982864).

The spelling of 115165421353 in words is "one hundred fifteen billion, one hundred sixty-five million, four hundred twenty-one thousand, three hundred fifty-three".