Base | Representation |
---|---|
bin | 1010011110011010001010… |
… | …0010011100000000000001 |
3 | 1111210001202202122221111112 |
4 | 2213212202202130000001 |
5 | 3002200402232212103 |
6 | 40255025430453105 |
7 | 2266054143610151 |
oct | 247464242340001 |
9 | 44701682587445 |
10 | 11517534257153 |
11 | 3740616910321 |
12 | 1360212b04195 |
13 | 657139152c02 |
14 | 2bb6473ca761 |
15 | 14e8e6847cd8 |
hex | a79a289c001 |
11517534257153 has 2 divisors, whose sum is σ = 11517534257154. Its totient is φ = 11517534257152.
The previous prime is 11517534257149. The next prime is 11517534257191. The reversal of 11517534257153 is 35175243571511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10368032923249 + 1149501333904 = 3219943^2 + 1072148^2 .
It is a cyclic number.
It is not a de Polignac number, because 11517534257153 - 22 = 11517534257149 is a prime.
It is not a weakly prime, because it can be changed into another prime (11517534257353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5758767128576 + 5758767128577.
It is an arithmetic number, because the mean of its divisors is an integer number (5758767128577).
Almost surely, 211517534257153 is an apocalyptic number.
It is an amenable number.
11517534257153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11517534257153 is an equidigital number, since it uses as much as digits as its factorization.
11517534257153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2205000, while the sum is 50.
The spelling of 11517534257153 in words is "eleven trillion, five hundred seventeen billion, five hundred thirty-four million, two hundred fifty-seven thousand, one hundred fifty-three".
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